A) UN
B) 15 N
C) 33 N
D) 30 N
Correct Answer: C
Solution :
As normality \[=\frac{\text{Weight}\,\text{per}\,\text{cent }\!\!\times\!\!\text{ Density }\!\!\times\!\!\text{ 10}}{\text{Eqeuivalent}\,\text{weight}}\] \[=\frac{70\times 1.54\times 10}{98/3}\] \[=33\,N\] Hence, the correct option is (c).You need to login to perform this action.
You will be redirected in
3 sec