A) \[\frac{1}{2}(M+m)g\]
B) \[(M+m)g\]
C) \[(M-m)g\]
D) \[(M+2m)g\]
Correct Answer: A
Solution :
Let T = tension in the rope = Force exerted by the nan on the rope = Force exerted by the rope on he man. N = normal reaction between man and frame. For equilibrium, \[T+N=mg,\,T=N+Mg.\] Solving the above relations, we get, \[T=\frac{1}{2}(M+m)g\] Hence, the correction option is [a].You need to login to perform this action.
You will be redirected in
3 sec