A) 24.8 eV
B) 12.4 eV
C) 6.2 eV
D) 10.2 eVs
Correct Answer: B
Solution :
\[\lambda =\frac{hc}{eV}=\frac{1240}{v}\,nm\] \[100=\frac{1240}{v}\]or \[V=\frac{1240}{100}=12.4V\] \[\therefore \] \[E=eV=12.4\,eV\] Hence, the correction option is [b].You need to login to perform this action.
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