A) \[\frac{\pi }{3}\]
B) \[\frac{2\pi }{3}\]
C) \[\frac{\pi }{6}\]
D) \[\frac{\pi }{4}\]
Correct Answer: B
Solution :
\[{{A}^{2}}=a_{1}^{2}+a_{2}^{2}+2{{a}_{1}}{{a}_{2}}\cos \phi \] Here, \[\phi ={{\phi }_{1}}-{{\phi }_{2}},A={{a}_{1}}={{a}_{2}}=a\] Putting there values, \[\cos \phi =-\frac{1}{2}\]or \[\phi =2\pi /3.\] Hence, the correction option is [b].You need to login to perform this action.
You will be redirected in
3 sec