A) 2 : 1
B) 1 : 2
C) 1 : 1
D) \[1:\sqrt{2}\]
Correct Answer: C
Solution :
\[{{y}_{1}}=10\sin \left( 3\pi t+\frac{\pi }{4} \right)\] \[{{y}_{2}}=10\left[ \frac{1}{2}\sin 3\pi t+\frac{\sqrt{3}}{2}\cos 3\pi t \right]\] \[=10[cos{{60}^{o}}sin3\pi t+sin{{60}^{o}}cos3\pi t]\] \[=10[\sin ({{60}^{o}}+3\pi t)]\] \[=10\sin (3\pi t+{{60}^{o}})\] \[\therefore \]ratio of amplitudes \[=1:1\] Hence, the correction option is [c].You need to login to perform this action.
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