A) 20 N
B) 40 N
C) 10 N
D) 32 N
Correct Answer: D
Solution :
Common acceleration, \[a=\frac{F}{{{m}_{1}}+{{m}_{2}}+{{m}_{3}}}=\frac{40}{10+6+4}=2\,m/{{s}^{2}}\] Equation of motion of \[{{m}_{3}}\]is \[{{T}_{3}}-{{T}_{2}}={{m}_{3}}a\] \[40-{{T}_{2}}=4\times 2,{{T}_{2}}=32\,N\] Hence, the correction option is [d].You need to login to perform this action.
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