A) \[{{B}^{-1}}\]
B) R
C) \[{{r}^{2}}\]
D) r
Correct Answer: C
Solution :
\[\varepsilon =\frac{d\Phi }{dt}\Rightarrow \frac{{{\Phi }_{2}}}{{{\Phi }_{1}}}\int_{{{\Phi }_{1}}}^{{{\Phi }_{2}}}{d\Phi =\Delta \Phi =\int_{{}}^{{}}{\varepsilon dt}}\] The total charge flown in the loop \[q=\int_{{}}^{{}}{Idt}\] or \[q=\int_{{}}^{{}}{\frac{\varepsilon }{R}dt}=\frac{\Delta \Phi }{R}=\frac{B\pi {{r}^{2}}}{R}\] i.e., \[q\propto B,\,q\propto {{r}^{2}},\]and \[q\propto \frac{1}{R}\] Hence, the correction option is [c].You need to login to perform this action.
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