A) 3 A
B) 9 A
C) \[\sqrt{3A}\]
D) \[\sqrt[3]{3A}\]
Correct Answer: C
Solution :
\[{{t}^{2}}=9{{t}^{2}}\] \[\therefore \]Mean square current \[=\frac{\int_{0}^{1}{9{{t}^{2}}dt}}{\int_{0}^{1}{dt}}=3\] \[\therefore \]\[{{i}_{rms}}=\sqrt{3}A\] Hence, the correction option is [c].You need to login to perform this action.
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