A) 1 : 2
B) 1 : 3
C) 2 : 1
D) 3 : 1
Correct Answer: D
Solution :
Velocity given by \[OA=\tan {{60}^{o}}=\sqrt{3}\,m/s\] Velocity given by \[AB={{\tan }^{{{30}^{o}}}}=-\frac{1}{\sqrt{3}}\,m/s\] Required ratio\[=\frac{\sqrt{3}}{1/\sqrt{3}}=3:1\] Hence, the correction option is [d].You need to login to perform this action.
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