A) 1 : 1
B) 3 : 2
C) 2 : 3
D) 1 : 3
Correct Answer: B
Solution :
During charging \[{{\tau }_{{{L}_{1}}}}=\frac{L}{2R}\] and during discharging \[{{\tau }_{{{L}_{2}}}}=\frac{L}{3R}\]You need to login to perform this action.
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