A)
B)
C)
D)
Correct Answer: B
Solution :
Let 2 a be the side of the triangle and b the length AE. \[\frac{AH}{AE}=\frac{GH}{EC},\]\[\therefore \]\[GH=\frac{AH}{AE}CE\] or \[GH=\frac{(b-vt)}{b}.a=a-=\left( \frac{a}{b}vt \right)\] \[\therefore \]\[FG=2GH=2\left[ a-\frac{a}{b}vt \right]\] Induced \[e\,m\,f\,e=Bv(FG)=2B\left( va-\frac{a}{b}vt \right)\] or \[i={{K}_{1}}-{{K}_{2}}tv\] Thus \[i-t\]graph is a straight line. Hence, the correction option is [b].You need to login to perform this action.
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