A) \[\frac{mx}{{{(m+1)}^{2}}}\]
B) \[\frac{mx}{{{(m-1)}^{2}}}\]
C) \[\frac{{{(m+1)}^{2}}x}{m}\]
D) \[\frac{{{(m-1)}^{2}}x}{m}\]
Correct Answer: A
Solution :
\[-m=-\frac{v}{u}\Rightarrow v=mu\] According to problem,\[u+v=x.u=\frac{x}{1+m},\] \[v=\frac{mx}{1+m}\] By the formula \[\frac{1}{f}=\frac{1}{u}+\frac{1}{v},f=\frac{mx}{{{(m+1)}^{2}}}\] Hence, the correction option is [a].You need to login to perform this action.
You will be redirected in
3 sec