A) 32 N
B) 4 N
C) 2 N
D) 8 N
Correct Answer: D
Solution :
Maximum force of friction, \[{{f}_{\max }}=\mu \,mg=0.8\times 4\times 10\]\[\times \,32\,N\]and applied force at \[t=2\,s\]is \[F=k{{t}^{2}}=2{{(2)}^{2}}=8N\] The body fails to move. Hence the force of friction at t = 2 s is equal to applied force = 8 N. Hence, the correction option is [d].You need to login to perform this action.
You will be redirected in
3 sec