A) \[0{}^\circ \]
B) \[60{}^\circ \]
C) \[90{}^\circ \]
D) \[180{}^\circ \]
Correct Answer: C
Solution :
As \[|\vec{A}+\vec{B}|\,=\,|\vec{A}-\vec{B}|\] so \[{{A}^{2}}+{{B}^{2}}+2AB\cos \theta ={{A}^{2}}+{{B}^{2}}-2AB\cos \theta \] or \[4AB\cos \theta =0\]or \[\cos \theta =\text{i}\text{.e}\text{.}={{90}^{o}}.\] Hence, the correction option is [c].You need to login to perform this action.
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