A) \[\frac{3{{\mu }_{0}}\ell }{2\pi a}\]
B) \[\frac{9{{\mu }_{0}}\ell }{2\pi a}\]
C) \[\frac{3\sqrt{3}{{\mu }_{0}}\ell }{2\pi a}\]
D) None of these
Correct Answer: D
Solution :
\[{{i}_{ABC}}=\frac{R}{2R+R}i=\frac{i}{3}\] \[{{i}_{AC}}=\frac{2R}{2R+R}i=\frac{2i}{3}\] Magnetic field at point O (centre) \[\frac{{{\mu }_{0}}(i/3)}{4\pi d}(\sin {{60}^{o}}+\sin {{60}^{o}})+\frac{{{\mu }_{0}}(i/3)}{4\pi d}(\sin {{60}^{o}}+\sin {{60}^{o}})\]\[-\frac{{{\mu }_{0}}(2i/3)}{4\pi d}(\sin {{60}^{o}}+\sin {{60}^{o}})=0\] Hence, the correction option is [d].You need to login to perform this action.
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