(i)\[F{{e}^{2+}}+2e\to Fe(s);{{E}^{o}}=-0.44\,V.\] |
(ii)\[2{{H}^{+}}(aq)+\frac{1}{2}{{O}_{2}}(g)+2e\to {{H}_{2}}O(l);{{E}^{o}}=+1.23\,V.\] |
A) \[-0.79\,V\]
B) \[-1.67\,V\]
C) \[1.67\,V\]
D) \[0.79\,V\]
Correct Answer: C
Solution :
Subtracting equation (i) from (ii) we get equation 3 as follows: \[Fe\,(s)+2{{H}^{+}}+1/2{{O}_{2}}\to F{{e}^{2+}}(aq)+{{H}_{2}}O(l)\] (3) So, \[{{E}^{o}}={{E}^{o}}_{2}-{{E}^{o}}_{1}\] \[=+1.23-(-0.44)\] \[=+1.67\,V\] Hence, the correct option is [c].You need to login to perform this action.
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