A) \[\sqrt{\frac{\mu }{\alpha }}\]
B) \[\frac{\mu }{\alpha }\]
C) \[\frac{1}{\sqrt{\mu \alpha }}\]
D) None of these
Correct Answer: A
Solution :
As shown in the figure, the bead will start slipping, when centripetal force exceeds the force of friction. i.e., \[m{{\omega }^{2}}L=\mu R=\mu m({{a}_{t}})\] Where \[{{a}_{t}}=\]tangential acceleration\[=L\,\alpha \] Also, \[\omega =\alpha t\]\[\therefore \,\,m{{(\alpha t)}^{2}}L=\mu m(L\alpha )\] \[t=\sqrt{\frac{\mu }{\alpha }}\] Hence, the correction option is [a],You need to login to perform this action.
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