A) 12.4
B) 1.6
C) 2.2
D) 13.4
Correct Answer: B
Solution :
\[{{N}_{1}}{{V}_{1\,base}}-{{N}_{2}}{{V}_{2acid}}={{N}_{R}}({{V}_{1}}+{{V}_{2}})\] \[\frac{1}{10}\times V-\frac{1}{20}\times V={{N}_{R}}\times 2\times V\] \[\frac{0.05}{2}={{N}_{R}}\] \[{{N}_{R}}=0.025\,\] \[[{{H}^{+}}]=0.025\,M\] \[pH=-\log [0.025]=1.6.\] Hence, the correct option is [b].You need to login to perform this action.
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