A) \[{{[Ag{{(N{{H}_{3}})}_{2}}]}^{2+}},{{[Ag{{(CN)}_{2}}]}^{3-}}\]and\[{{[Ag{{({{S}_{2}}{{O}_{3}})}_{2}}]}^{2-}}\]
B) \[{{[Ag{{(N{{H}_{3}})}_{2}}]}^{+}},{{[Ag{{(CN)}_{2}}]}^{3-}}\]and\[{{[Ag{{({{S}_{2}}{{O}_{3}})}_{2}}]}^{2-}}\]
C) \[{{[Ag{{(N{{H}_{3}})}_{2}}]}^{+}},{{[Ag{{(CN)}_{2}}]}^{-}}\]and\[{{[Ag{{({{S}_{2}}{{O}_{3}})}_{2}}]}^{3-}}\]
D) \[{{[Ag{{(N{{H}_{3}})}_{4}}]}^{2+}},{{[Ag{{(CN)}_{2}}]}^{3-}}\]and\[{{[A{{g}_{2}}{{({{S}_{2}}{{O}_{3}})}_{2}}]}^{2-}}\]
Correct Answer: C
Solution :
\[AgCl+2N{{H}_{4}}OH\to [Ag{{(N{{H}_{3}})}_{2}}]Cl+2{{H}_{2}}O\] \[AgCl+2KCN\to K[Ag{{(CN)}_{2}}]+KCl\] \[AgCl+N{{a}_{2}}{{S}_{2}}{{O}_{3}}\to N{{a}_{3}}[Ag{{({{S}_{2}}{{O}_{3}})}_{2}}]+NaCl\] Hence, the correct option is [c].You need to login to perform this action.
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