A) \[\sqrt{2}\]
B) \[\frac{1}{2}\sqrt{2}\]
C) \[2\sqrt{2}\]
D) 2
Correct Answer: C
Solution :
\[\lambda =\frac{h}{P}=\frac{h}{\sqrt{2Km}}=\frac{h}{\sqrt{2qVm}}\] \[\therefore \]\[\frac{{{\lambda }_{P}}}{{{\lambda }_{\alpha }}}=\sqrt{\frac{{{q}_{P}}}{{{q}_{\alpha }}}\times \frac{{{m}_{\alpha }}}{{{m}_{P}}}}=\sqrt{2\times 4}=2\sqrt{2}\] Hence, the correction option is [c].
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