A) 40.2
B) 47.2
C) 12.5
D) 21.5
Correct Answer: A
Solution :
\[{{E}^{o}}=\frac{0.0591}{n}\log {{K}_{eq}}\] So, \[\log \,{{K}_{eq}}=\frac{{{E}^{o}}\times n}{0.0591}=\frac{1.20\times 2}{00591}=40.6.\] Hence, the correct option is [a].You need to login to perform this action.
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