A) 300 m/s
B) 150 m/s
C) 600 m/s
D) 75 m/s
Correct Answer: B
Solution :
\[{{v}_{rms}}=\sqrt{\frac{3RT}{2M}}\]or \[300=\sqrt{\frac{3RT}{2M}}\] and \[v_{rms}^{'}=\sqrt{\frac{3R(T/2)}{2M}}=\frac{1}{2}\times 300=150\,m/s.\] Hence, the correction option is [b].You need to login to perform this action.
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