A) 0.025 m
B) 0.015 m
C) 0.001 m
D) 0.002 m
Correct Answer: A
Solution :
For first resonance \[{{\ell }_{1}}+e=\lambda /4\] Where e is the end correction For second resonance\[{{\ell }_{2}}+e=\frac{3\lambda }{4}\] So, \[e=\frac{{{\ell }_{2}}-3{{\ell }_{1}}}{2}=0.025\,m.\] Hence, the correction option is [a].You need to login to perform this action.
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