A) \[9\times {{10}^{4}}\]volt
B) \[6\times {{10}^{-4}}\] volt
C) \[3\times {{10}^{-4}}\] volt
D) \[2\times {{10}^{4}}\] volt
Correct Answer: B
Solution :
Vertical component of earth's magnetic field \[B=6\times {{10}^{-5}}Wb/{{m}^{2}}\] distance between the meter gauge rail \[l\] = 1 metre speed of train \[V=36\text{ }km/hr.\] \[=\frac{36\times 5}{18}=10\,m/s.\] The induced potential difference is given by \[\varepsilon =B\upsilon l=6\times {{10}^{-5}}\times 10\times 1\] \[=6\times {{10}^{-4}}\] voltYou need to login to perform this action.
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