A) \[3.4\times {{10}^{3}}J\]
B) \[2.7\times {{10}^{2}}J\]
C) \[1.2\times {{10}^{2}}J\]
D) none of these
Correct Answer: A
Solution :
We know that the kinetic energy of \[1g\] molecule of an ideal gas is \[E=\frac{3}{2}\,RT\] Here \[R=8.31\,J/mol\,K\] and \[~T={{273}^{o}}K\] \[\therefore \] \[E=\frac{3}{2}\times 8.31\times 273=3.4\times {{10}^{3}}J\]You need to login to perform this action.
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