A) \[990cm/{{s}^{2}}\]
B) \[394\,cm/{{s}^{2}}\]
C) \[250\,cm/{{s}^{2}}\]
D) none of these
Correct Answer: B
Solution :
Here, length of the string \[l=40\,cm\] Time period \[T=\frac{20}{10}\,2\,\sec \] and angular velocity \[\omega =\frac{2\pi }{T}=\frac{3\times 3.14}{2}=3.14\] Hence the magnitude of acceleration is \[\alpha ={{\omega }^{2}}\times l={{(3.14)}^{2}}\times 40\] \[=394\,cm/{{s}^{2}}\]You need to login to perform this action.
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