A) \[5.14\times {{10}^{21}}\]
B) \[1.28\times {{10}^{21}}\]
C) \[1.71\times {{10}^{21}}\]
D) \[2.57\times {{10}^{21}}\]
Correct Answer: D
Solution :
One unit cell of \[NaCl\] contains \[4\,\,NaCl\] units i.e. has mass \[=\frac{4\times 58.5}{6.02\times {{10}^{23}}}\,g\] \[\therefore \] Number of unit cells in \[1\,g\] \[=\frac{6.02\times {{10}^{23}}}{4\times 58.5}=2.57\times {{10}^{21}}\]You need to login to perform this action.
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