A) \[{{A}_{2}}{{B}_{3}}\]
B) \[A{{B}_{3}}\]
C) \[{{A}_{3}}B\]
D) \[{{A}_{3}}{{B}_{2}}\]
Correct Answer: B
Solution :
Number of corner atom \[(A)=8\times \frac{1}{8}=1\] Number of face centre atom \[(B)=6\times \frac{1}{2}=3\] Hence, formula of the compound is \[A{{B}_{3}}\].You need to login to perform this action.
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