A) 50
B) 40
C) 30
D) 20
Correct Answer: C
Solution :
The resistance of the galvanometer \[G=6\Omega \] maximum current through the galvanometer\[{{i}_{g}}=2\] amp Final current in ammeter \[i=6\] amp The current through the galvanometer is given by \[{{i}_{g}}=\frac{S}{S+G}\times i\] (where S is the resistance of shunt) \[\Rightarrow \] \[2=\frac{S}{S+6}\times 6\] \[\Rightarrow \] \[2S+12=6S.\] \[\Rightarrow \] \[4S=12\] \[\Rightarrow \] \[S=3\Omega \].You need to login to perform this action.
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