A) \[5.7\]
B) \[5.6\]
C) \[5.4\]
D) \[2.0\]
Correct Answer: A
Solution :
\[0.12\,PPm=0.12\,g\] In \[{{10}^{6}}\,mL\] \[[{{H}^{+}}]=[S{{O}_{2}}]\] \[\therefore \] \[[{{H}_{2}}S{{O}_{3}}]=\frac{0.12}{64}\times {{10}^{-3}}m\] \[pH=5.7\]You need to login to perform this action.
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