A) \[{{a}_{0}}\] from the nucleus
B) \[1.5\,{{a}_{0}}\] from the nucleus
C) \[2\,{{a}_{0}}\] from the nucleus
D) none of these is correct
Correct Answer: C
Solution :
For 2s orbital, the nodal surface exists at a distance of \[2{{a}_{0}}\]You need to login to perform this action.
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