A) \[2.5\]
B) \[1.5\]
C) \[1.8\]
D) none of these
Correct Answer: B
Solution :
To find the value of \[\gamma ,\] for mixture we take average value of \[\gamma =\left( \frac{{{C}_{p}}}{{{C}_{\upsilon }}} \right){{\alpha }_{\upsilon }}\] \[{{C}_{\upsilon }}\] for monoatomic gas \[=\frac{3}{2}R\] ?..(i) \[{{C}_{\upsilon }}\] for diatomic gas \[=\frac{5}{2}R\] So, average \[{{C}_{\upsilon }}=\frac{\frac{3}{2}R+\frac{5}{2}R}{2}=2R\] Thus \[{{C}_{p}}\] for mixture or average \[{{C}_{p}}\] \[={{C}_{\upsilon }}+R=2R+R\] \[=3R\] ?..(ii) Therefore the value of y for the mixture is given by \[\gamma =\left( \frac{{{C}_{p}}}{{{C}_{\upsilon }}} \right){{a}_{\upsilon }}=\frac{3R}{2R}\] (from (0 and (ii))You need to login to perform this action.
You will be redirected in
3 sec