A) Isohypophosphoric acid
B) Diphosphorus acid
C) Diphosphoric acid
D) Hypophosphoric acid
Correct Answer: D
Solution :
Isohyposphoric acid \[({{H}_{4}}{{P}_{2}}{{O}_{6}})\] \[H-\underset{OH}{\mathop{\overset{O}{\mathop{\overset{||}{\mathop{\underset{|}{\mathop{P}}\,}}\,}}\,}}\,-O-\underset{OH}{\mathop{\overset{O}{\mathop{\overset{||}{\mathop{\underset{|}{\mathop{P}}\,}}\,}}\,}}\,-OH\] Diphosphorus acid \[({{H}_{4}}{{P}_{2}}{{O}_{5}})\] \[H-\underset{OH}{\mathop{\overset{O}{\mathop{\overset{||}{\mathop{\underset{|}{\mathop{P}}\,}}\,}}\,}}\,-O-\underset{OH}{\mathop{\overset{O}{\mathop{\overset{||}{\mathop{\underset{|}{\mathop{P}}\,}}\,}}\,}}\,-OH\] Diphosphoric acid \[({{H}_{4}}{{P}_{2}}{{O}_{7}})\] Hypophosphoric acid \[({{H}_{4}}{{P}_{2}}{{O}_{6}})\]You need to login to perform this action.
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