A) 0
B) \[\frac{1}{2}B\upsilon \pi {{R}^{2}},\] and M is at a higher potential
C) \[\pi RB\upsilon ,\]and Q is at a higher potential
D) \[2RB\upsilon ,\] and Q is at a higher potential
Correct Answer: D
Solution :
The emf induced in a conductor does not depend on its shape but only on its end points. As a simple application of this principle, replace the actual conductor by an imaginary straight conductor joining its two ends. Hence, the correction option is (d).You need to login to perform this action.
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