A) \[\frac{3}{2}{{P}_{0}}\]
B) \[\frac{4}{3}{{P}_{0}}\]
C) \[\frac{5}{3}{{P}_{0}}\]
D) \[2{{P}_{0}}\]
Correct Answer: B
Solution :
Let \[{{V}_{0}}\]be the volume of each container is \[n=\frac{{{P}_{0}}{{V}_{0}}}{R{{T}_{0}}}\] Finally, number of moles in the two containers are \[{{n}_{1}}=\frac{{{P}_{0}}{{V}_{0}}}{R{{T}_{0}}}\]and \[{{n}_{2}}=\frac{P{{V}_{0}}}{R(2{{T}_{0}})}\] Total number of moles remain the same \[\Rightarrow \]\[{{n}_{1}}+{{n}_{2}}=n+n\] \[\Rightarrow \]\[\frac{P{{V}_{0}}}{R{{T}_{0}}}+\frac{P{{V}_{0}}}{2R{{T}_{0}}}=\frac{2{{P}_{0}}{{V}_{0}}}{R{{T}_{0}}}\]\[\therefore \]\[P=\frac{4}{3}{{P}_{0}}\] Hence, the correction option is (b).You need to login to perform this action.
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