A) \[{{I}_{o}}\]
B) \[\frac{{{I}_{o}}}{2}\]
C) \[\frac{{{I}_{o}}}{4}\]
D) \[\frac{3{{I}_{o}}}{4}\]
Correct Answer: D
Solution :
\[I={{I}_{0}}{{\cos }^{2}}\frac{\phi }{2}={{I}_{o}}{{\cos }^{2}}\frac{60}{2}={{I}_{0}}\times {{\left( \frac{\sqrt{3}}{2} \right)}^{2}}=\frac{3{{I}_{0}}}{4}\] Hence, the correction option is (d).You need to login to perform this action.
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