A) \[V[dg-\rho (g+a)]\]
B) \[V(g+a)(d-\rho )\]
C) \[V(d-\rho )g\]
D) None of these
Correct Answer: B
Solution :
If container is at rest, \[T=dV\,g-\rho Vg=(d-\rho )V\,g\] When container has an upward acceleration a, the effective gravity in frame of container is g' = g + a downwards. \[\therefore \]\[T=(d-\rho )Vg'=(d-\rho )V(g+a)\] Hence, the correction option is (b).You need to login to perform this action.
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