A) \[\frac{2}{3}hv\]
B) \[\frac{hv}{2}\]
C) \[\frac{hv}{3}\]
D) 0
Correct Answer: A
Solution :
\[hv-\phi =\frac{1}{2}mv_{\max }^{2}\] Also, \[h(2v)-{{\phi }_{0}}=\frac{1}{2}m{{(2{{v}_{\max }})}^{2}}\] \[\Rightarrow \]\[2hv-{{\phi }_{0}}=4(hv-{{\phi }_{0}})\]\[\therefore \]\[{{\phi }_{0}}=\frac{2}{3}hv\] Hence, the correction option is (a).You need to login to perform this action.
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