A) Neutral
B) More acidic
C) Basic
D) Unaffected
Correct Answer: A
Solution :
\[pH=5\] \[[{{H}_{3}}{{O}^{+}}]={{10}^{-pH}}={{10}^{-5}}M\] \[{{M}_{1}}={{10}^{-5}},let\,{{V}_{1}}=x\] \[{{M}_{2}}=?,\,{{V}_{2}}=100x\] According to dilution law \[{{M}_{4}}{{V}_{1}}={{M}_{2}}{{V}_{2}}\] \[{{10}^{-5}}x={{M}_{2}}100x\] \[\frac{{{10}^{-5}}x}{100x}={{M}_{2}}\] \[={{10}^{-7}}M={{M}_{2}}\] \[[{{H}_{3}}O]={{10}^{-7}}M+{{10}^{-7}}M\] (From water) \[=2\times {{10}^{-7}}\,M\] \[pH=-\log [{{H}_{2}}{{O}^{+}}]\] \[=-\log 2\times {{10}^{-7}}=6.69\] Hence, the solution becomes almost neutral. Hence, the correct option is (a).
You need to login to perform this action.
You will be redirected in
3 sec
