A) 0.03 eV
B) 0.30 eV
C) 0.45 eV
D) 0.60 eV
Correct Answer: B
Solution :
Here, \[E=6\times {{10}^{5}}\,V{{m}^{-1}};\,d=500\times {{10}^{-9}}\,m\] Here, height of potential barrier, \[{{V}_{B}}=Ed=6\times {{10}^{5}}\times 500\times {{10}^{-9}}=0.30\,V\] Maximum K.E. of and electron to cross the potential barrier \[=e{{V}_{B}}=e\times (0.30\,V)=0.30\,eV.\] Hence, the correction option is (b).You need to login to perform this action.
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