A) A = 2B
B) \[A=\frac{B}{2}\]
C) A = B
D) AB = 1
Correct Answer: C
Solution :
Let the resultant of \[\vec{A}\]and \[\vec{B}\]be \[\vec{R}\]as shown in figure Applying. Sine rule in the triangle we get \[\frac{A}{\sin \alpha }=\frac{B}{\sin \frac{\theta }{2}}\]or, \[\frac{A}{\sin \frac{\theta }{2}}=\frac{B}{\sin \frac{\theta }{2}}\] or \[A=B\] Hence, the correction option is (c).You need to login to perform this action.
You will be redirected in
3 sec