A) \[4\times {{10}^{-5}}H\]
B) \[3\times {{10}^{-5}}H\]
C) \[2\times {{10}^{-5}}H\]
D) \[1.8\times {{10}^{-2}}H\]
Correct Answer: D
Solution :
\[\left| {{e}_{s}} \right|={{N}_{s}}\frac{d{{\Phi }_{s}}}{dt}\]and \[\left| {{e}_{s}} \right|=M\frac{d{{I}_{s}}}{dt}\,\therefore \,{{N}_{s}}\frac{d{{\Phi }_{s}}}{dt}=M\frac{d{{I}_{s}}}{dt}\] \[M={{N}_{s}}\frac{d\Phi }{d{{I}_{p}}}=\frac{600\times 9.00\times {{10}^{-5}}}{3.0}=1800\times {{10}^{-5}}H.\] Hence, the correction option is(d).You need to login to perform this action.
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