A) \[\frac{mg}{\cos \theta }\]
B) \[mg\,\sin \theta \]
C) \[mg{{\sin }^{2}}\theta \]
D) \[mg\cos \theta \sin \theta \]
Correct Answer: D
Solution :
For the block, \[N=mg\cos \theta \] For the horizontal equilibrium of the wedge, \[F=N\sin \theta \] \[\therefore \]\[F=mg\cos \theta \sin \theta \] Hence, the correction option is (d).You need to login to perform this action.
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