A) 100 m/s in the horizontal direction
B) 300 m/s in the horizontal direction
C) 300 m/s in a direction making an angle of \[60{}^\circ \] with the horizontal
D) 200 m/s in a direction making an angle of \[60{}^\circ \] with the horizontal
Correct Answer: B
Solution :
Momentum of ball before explosion at the highest point \[=mv\hat{i}=mu\cos {{60}^{o}}\hat{i}\] \[=m\times 200\times \frac{1}{2}\hat{i}=100\,m.\hat{i}\,kg\,.m/s\] Let the velocity of third part after explosion is V. After explosion momentum of system \[=\overrightarrow{{{P}_{1}}}+\overrightarrow{{{P}_{2}}}+\overrightarrow{{{P}_{3}}}\] \[=\frac{m}{3}\times 100\hat{j}-\frac{m}{3}\times 100\,\hat{j}+\frac{m}{3}\times V\hat{i}\,100m\hat{i}\,\] or, \[V=300\,m/s\] Here, the correction option is (b).You need to login to perform this action.
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