A) \[g,g\]
B) \[g-a,\,g-a\]
C) \[g-a,\,g\]
D) \[a,g\]
Correct Answer: C
Solution :
Let apparent weight of ball from the frame of the lift\[=w'\] \[\therefore \] \[w'=w-R\] Where, the pseudo force, R = ma acts upward \[\therefore \]\[w'=mg-ma=m(g-a)\] Hence apparent acceleration in the lift is g - a. No if the man is standing stationary on the ground, then the apparent acceleration of the falling ball is g. Hence, the correction option is [c].You need to login to perform this action.
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