A) 0
B) \[({{m}_{1}}+{{m}_{2}})g{{t}_{0}}\]
C) \[2({{m}_{1}}+{{m}_{2}})g{{t}_{0}}\]
D) \[\frac{1}{2}({{m}_{1}}+{{m}_{2}})g{{t}_{0}}\]
Correct Answer: C
Solution :
\[\left| ({{m}_{1}}{{{\vec{v}}}_{1}}+{{m}_{2}}{{{\vec{v}}}_{2}})-({{m}_{1}}{{{\vec{u}}}_{1}}+{{m}_{2}}{{{\vec{u}}}_{2}}) \right|\] \[\text{=}\left| \text{change}\,\text{in momentum of the two particle} \right|\] \[\text{=}\left| \text{external}\,\text{force}\,\text{on}\,\text{ethe}\,\text{system}\,\text{X}\,\text{time}\,\text{interval} \right|\] \[=({{m}_{1}}{{m}_{2}})g(2{{t}_{0}})\] \[=2({{m}_{1}}+{{m}_{2}})g{{t}_{0}}\] Hence, the correction option is [c].You need to login to perform this action.
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