A) \[sp\]
B) \[~s{{p}^{2}}\]
C) \[~s{{p}^{3}}\]
D) \[~s{{p}^{2}}{{d}^{2}}\]
Correct Answer: B
Solution :
By using hybridization number \[=S.A+\frac{1}{2}[V.E-shared\,{{e}^{-}}\pm charge]\] In \[BC{{l}_{3}}\]hybridization number \[=3+\frac{1}{2}[3-3]=3\] In\[~BC{{l}_{3}},\] B-atom will be \[s{{p}^{2}}\]hybridized. Hence, the correct option is (b).
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