A) 8.4 litres
B) 2.2 litres
C) 5.5 litres
D) 3.9 litres
Correct Answer: A
Solution :
By using the relation Strength = Normality \[\times \]Equivalent weight \[=1.5\times 17=25.5\] As hydrogen peroxide dissociates as follows: \[2{{H}_{2}}{{O}_{2}}\to 2{{H}_{2}}O+{{O}_{2}}\] Molecular weight of 2 molecule of \[{{H}_{2}}{{O}_{2}}=2[(1\times 2)+(16\times 2)]\] \[=2\,[2+32]=68\] A 68 g of \[{{H}_{2}}{{O}_{2}}\]liberates 22.4 litre of \[{{O}_{2}}\]at N.T.P. So, 25.5 of \[{{H}_{2}}{{O}_{2}}\]will liberate \[=\frac{22.4\times 25.5}{68}\] \[=8.4\,\text{litre}\,\text{of}\,\]\[{{O}_{2}}.\] Hence, the correct option is (a).
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