A) 0
B) 150 N
C) \[150\sqrt{3}\,N\]
D) 300 N
Correct Answer: C
Solution :
We know that \[F=\Delta p/\Delta t.[\Delta p=\]\[\text{change}\,\text{in}\,\text{momentum}]\] \[\Delta p=2\,mv\,\sin \theta \] \[=2\times 3\times 10\sin {{60}^{o}}=30\sqrt{3}\]\[F=\frac{\Delta p}{\Delta t}=\frac{30\sqrt{3}}{0.2}=150\sqrt{3}\,N\] Hence, the correction option is [c].You need to login to perform this action.
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