A) \[{{0}^{o}}\]
B) \[{{90}^{o}}-{{\theta }^{o}}\]
C) \[{{90}^{o}}\]
D) \[{{0}^{o}}\]
Correct Answer: C
Solution :
Making observations from the frame of the trolley, the situation appears as shown in figure, invoking conditions of equilibrium on the bob along \[x-\]axis yields \[T\cos \alpha +mg\sin \theta =ma\] \[T\cos \alpha =ma-mg\sin \theta \] \[T\cos \alpha =mg\sin \theta -mg\sin \theta \]\[[\because \,a=g\sin \theta ]\] \[\therefore \]\[T\cos \alpha =0\Rightarrow \alpha =\frac{\pi }{2}={{90}^{o}}\] Hence, the correction option is [c].You need to login to perform this action.
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